7p^2=54p

Solution for 7p^2=54p equation:

7p^2=54p

We move all terms to the left:

7p^2-(54p)=0

a = 7; b = -54; c = 0;
Δ = b2-4ac
Δ = -542-4·7·0
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-54}{2*7}=\frac{0}{14}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+54}{2*7}=\frac{108}{14}
=7+5/7
$